Answer:
x1=6 +i4.80 x2=6 -i4.80
Explanation:
Since 59 is a prime number we will use the quadratic formula to solve this problem:
x= (−b ± √(b^2−4ac)) ÷ 2a
Here a=1 b= -12 c=59
Plugging these values in the formula:
x= (12 ± √((-12)^2 -4(1)(59)) ÷2(1)
x=(12 ± √(144 - 236)) ÷2
x=(12 ± √-92) ÷ 2
As we know that √-1 =i and √-92 can be written as √92 × √-1 so:
x=(12 ± i√92) ÷2
x1= (12 +i 9.59) ÷2 x2= (12 -i 9.59)÷2
x1=6 +i4.80 x2=6 -i4.80
The given equation has no real solutions, both are imaginary.