Answer:
The value of f(x) =
when x=3 is 19, hence the correct option is ‘d’.
Solution:
A two degree polynomial equation is given in the question.
The equation is:
![F(x)=2 x^(2)+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2l9uzdkvrqhts83z6uxeujckdtu2agzk1d.png)
We need to find the value of f(x) when the value of x is 3.
To solve a question like this we have to substitute the given value of x in the given equation and then simplify it.
Now let's substitute the value of x in the given equation.
![F(x)=2(3)^(2)+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/scxxf94358hdlfmqumgeunp00ijzh31f20.png)
First we square the number 3 and then multiply it with 2 and then add 1.
This is done because of the BODMAS rule, in which multiplication is given higher preference as compared to addition.
On solving the equation we get,
F(x)=2×9+1
F(x)=18+1
F(x)=19.
Therefore the value of f(x) when x=3 is 19.
Hence the correct option is ‘d’.