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What volume does 0.87mol of H2O(g) occupy 36.2oC and 1.25 atm?

A
2.06L

B
17.6L

C
37.1L

D
317L

1 Answer

4 votes

Answer:

The answer is 17.66 L of volume occupy by water

Step-by-step explanation:

According to ideal gas equation, the volume is calculated

PV= nRT

where V = volume

P = Pressure =.

n = number of moles,

T = temperature

Where R = 0.08206 L atm mol-1K-1 is constant

Convert the temperature value from degree centigrade to kelvin 1 °C = 273.15 K

By putting the values in the above equation as we have to find the volume so by adjusting

V= nRT/ P n= 0.87 mol P= 1.25 atm T= 36.2 °C= 309.35 K

V= (0.87mol) x (0.08206 L atm mol-1K-1 )x (309.3 K)/ 1.25 atm

V= 22.08 L atm /1.25 atm

Volume = 17.66 L

User Ofer Herman
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