Question

For a fundraiser, a group plans to sell granola bars and bottles of water at the same prices as described in Part A. The group wants the income from the fundraiser to be at least $150. Choose the inequality to show the number of granola bars x and the number of bottles of water y that must be sold.

Answer 1

The inequality that shows the number of granola bars and bottles of water that must be sold to reach an income of at least $150 is xP + yQ ≥ 150.

Step-by-step explanation:

To determine the inequality that shows the number of granola bars and bottles of water that must be sold in order to achieve an income of at least $150, we can use the following information:

Let x be the number of granola bars and y be the number of bottles of water.

The price of each granola bar is $P and the price of each bottle of water is $Q.

The inequality that represents the fundraiser's income and quantity of items sold is:

Income ≥ $150
xP + yQ ≥ 150

Therefore, the inequality that shows the number of granola bars x and the number of bottles of water y that must be sold to reach an income of at least $150 is xP + yQ ≥ 150.

Answer 2

Incomplete question. The missing part read;

Ten granola bars and twelve bottles of water cost $23. Five granola bars and four bottles of water cost $10.

Options:

A. 1.4x + 0.75y > 150

B. 1.4x + 0.75y ≥ 150

C. 1.4x + 0.75 < 150

D. 1.4x + 0.75 ≤ 150

Answer:

B. 1.4x + 0.75y ≥ 150

Step-by-step explanation:

Remember, from the question we are told that the group wants the income from the fundraiser to be at least $150, meaning, they are not against having an income above $150 from the fundraiser, but a minimum of at least that amount.

Hence, among all the listed options, the correct inequality sign to represent the number of granola bars 'x' and the number of bottles of water 'y' that must be sold is the ≥ (equal to or greater than sign).