Question

A helicopter accelerates at 22 m/s2 from rest. How far will it have traveled after lifting off from a launch pad after 6.0 s?

Answer 1

The answer to your question is: d = 396 m

Step-by-step explanation:

Data

a = 22 m/s²

vo = 0 m/s

t = 6 s

d = ?

Formula

`d = vot + (at^(2) )/(2)`

`d = (0)(6) + ((22)(6)^(2) )/(2)`

d = 396 m