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The specific heat capacity of thallium is 0.128 J/gC. A sample of thallium weighing 32.9 g is heated from 49C to its melting point(303 C). Calculate the energy change involved.

User Svarrall
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1 Answer

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Answer:

Thallium absorbed 1069.645 J heat to reach to its melting point.

Step-by-step explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of thallium = 32.9 g

specific heat capacity of thallium = 0.128 j/g. °C

Initial temperature = 49 °C

Final temperature = 303 °C

Solution:

Change in temperature = T₂- T₁

ΔT = 303 °C - 49 °C = 254 °C

Formula:

Q = m.c. ΔT

Q = 32.9 g ×0.128 j/g. °C × 254 °C

Q = 1069.645 J

Thallium absorbed 1069.645 J heat to reach to its melting point.

User Jalone
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