Question

a car travelling at 50km/h from rest covers a distance of 10km in 40minutes. Calculate the acceleration​

Answer 1

`9.67\cdot 10^(-3)m/s^2`

Step-by-step explanation:

We can solve the problem by using the following suvat equation:

`v^2-u^2=2as`

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the car in this problem:

u = 0 (it starts from rest)

`v=50 km/h \cdot (1000)/(3600)=13.9 m/s` is the final velocity

s = 10 km = 10 000 m is the displacement

Solving for a, we find:

`a=(v^2-u^2)/(2s)=(13.9^2)/(2(10000))=9.67\cdot 10^(-3)m/s^2`