Question

Three forces act on a moving object. One force has a magnitude of 76.5 N and is directed due north. Another has a magnitude of 59.0 N and is directed due west. What must be the magnitude and direction of the third force, such that the object continues to move with a constant velocity?

Answer 1

F= 96.61 N

angle (θ) = 52.35°

Step-by-step explanation:

given,

One Force F₁ = 76.5 N

second force F₂ = 59 N

That means F₃ must equal –(F₁+F₂) so the net sum of the three is zero.

F₁+F₂, since they are orthogonal, is easy.

F₁+F₂ =

=
`√((76.5^2 + 59^2))`

= 96.61 N

`tan \theta = (f_y)/(f_x)`

`tan \theta = (76.5)/(59)`

`\theta = tan^(-1)(1.30)`

`\theta = 52.35^0`

Force is acting of magnitude F= 96.61 N

angle (θ) = 52.35°