Question

Atmospheric pressure at sea level is equal to a column of 760 mm Hg. Oxygen makes up 21 percent of the atmosphere by volume. The partial pressure of oxygen (PO2) in such conditions is _____. Atmospheric pressure at sea level is equal to a column of 760 mm Hg. Oxygen makes up 21 percent of the atmosphere by volume. The partial pressure of oxygen (PO2) in such conditions is _____. 21/760 16 mm Hg 760/21 120/75 160 mm Hg SubmitR

Answer 1

The partial pressure of oxygen (PO2) at sea level, given that the atmospheric pressure is 760 mm Hg, and oxygen constitutes 21% of the atmospheric volume, is 160 mm Hg.

Step-by-step explanation:

The partial pressure of oxygen (PO2) at sea level when the atmospheric pressure is 760 mm Hg, and oxygen makes up 21 percent of the atmosphere by volume can be calculated using the formula:

PO2 = Total atmospheric pressure × Percent content of oxygen (by volume)

Substituting the values:

PO2 = (760 mm Hg) × 0.21 = 160 mm Hg

Therefore, the partial pressure of oxygen at sea level is 160 mm Hg.

Answer 2

Answer: The partial pressure of oxygen is 160 mmHg

Step-by-step explanation:

We are given:

Percent of oxygen in air = 21 %

Mole fraction of oxygen in air =
`(21)/(100)=0.21`

To calculate the partial pressure of oxygen, we use the equation given by Raoult's law, which is:

`p_(O_2)=p_T* \chi_(O_2)`

where,

`p_(O_2)` = partial pressure of oxygen = ?

`p_T` = total pressure of air = 760 mmHg

`\chi_(O_2)` = mole fraction of oxygen = 0.21

Putting values in above equation, we get:

`p_(O_2)=760mmHg* 0.21\\\\p_(O_2)=160mmHg`

Hence, the partial pressure of oxygen is 160 mmHg