Question

A boy shoves his stuffed toy zebra down a frictionless chute. It starts at a height of 1.81 m above the bottom of the chute with an initial speed of 1.89 m/s . The toy animal emerges horizontally from the bottom of the chute and continues sliding along a horizontal surface with a coefficient of kinetic friction of 0.269 . How far from the bottom of the chute does the toy zebra come to rest? Assume ????=9.81 m/s2 .

Answer 1

7.4 m

Step-by-step explanation:

Friction is going to consume all of the initial energy:

`(1)/(2)m\ddot{x}^2+mgy=F_(friction)x=\mu mgx`

Solving for x:

`x=\frac{\ddot{x}^2}{2\mu g}+(y)/(\mu)`