1
I can't really be sure from the figure but I'll assume the top and bottom of these trapezoidal prisms are rectangles, as are two of the sides, the other two being isosceles trapezoids.
So the top is 6×6. It's hard to tell for sure but I'm going to assume the unlabeled bottomed edges are 6 so the bottom is 4×6 and two of the sides are 6×2. That leaves two trapezoids as the remaining faces, each with area

So we a total area of
A = 6×6 + 4×6 + 2×6×2 + 2×8.5 = 101
Answer: 101 square yards
3
Seems like the same problem with slightly different numbers, let's just write it
A = 10×6 + 4×10 + 2×4×10 + 2(1/2)(4+6)(3.9) = 219
Answer: 219 square meters