Answer:
The first 5 terms of the sequence are 4, 6, 9, 13 , 18
Explanation:
Given that f(n) = f(n − 1) + n and f(1) = 4 for n ≥ 2
f(1) = 4
f(2) = f(2 − 1) + 2 = f(1) + 2 = 4 + 2 = 6
f(3) = f(3 − 1) + 3 = f(2) + 3 = 6 + 3 = 9
f(4) = f(4 − 1) + 4= f(3) + 4 = 9 + 4 = 13
f(5) = f(5 − 1) + 5 = f(4) + 5 = 13 + 5 = 18
The first 5 terms of the sequence are 4, 6, 9, 13 , 18