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, list the first five terms of each sequence.
an = an−1 ÷ 2, where a1 = 50 for n ≥ 2

User Hind
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1 Answer

6 votes

Answer:

The first 5 terms of the sequence are 50,25,12.5,6.25,3.125

Explanation:

Given that


a_n=(a_(n-1))/(2), \texttt{where }a_1=50\texttt{ for n}\geq 2

So we have


a_1=50\\\\a_2=(a_(2-1))/(2)=(a_(1))/(2)=(50)/(2)=25\\\\a_3=(a_(3-1))/(2)=(a_(2))/(2)=(25)/(2)=12.5\\\\a_4=(a_(4-1))/(2)=(a_(3))/(2)=(12.5)/(2)=6.25\\\\a_5=(a_(5-1))/(2)=(a_(4))/(2)=(6.25)/(2)=3.125

The first 5 terms of the sequence are 50,25,12.5,6.25,3.125

User AmazingDayToday
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