Answer:
![B = \{3,4,5,6\}](https://img.qammunity.org/2022/formulas/mathematics/high-school/lajo9jqr32hv9p549rq0p5gpplf7yyn24i.png)
Explanation:
Given
![A = \{1,2,3,4,5\}](https://img.qammunity.org/2022/formulas/mathematics/high-school/j9cj1nluukehdm2rkihubsj0l0tu0qodf4.png)
![A\ n\ B = \{3,4,5\}](https://img.qammunity.org/2022/formulas/mathematics/high-school/ao2eax8tss12r4yjzenczxrrtezuom2qec.png)
![A\ u\ B = \{1,2,3,4,5,6\}](https://img.qammunity.org/2022/formulas/mathematics/high-school/7vkgx8p90kuukigygbaxsrznfj55diexoo.png)
Required
Find set B
means that the common elements in A and B are 3, 4 and 5.
This implies that:
A subset of B are:
![x = \{3,4,5\}](https://img.qammunity.org/2022/formulas/mathematics/high-school/dnz3zb1u8e00ikhlbqgrfqkksyrzx4u0cs.png)
And it also means that
are not elements of B.
The remaining elements (y) of B are then calculated as follows:
![y = (A\ u\ B) - (\{1,2\}\ u\ x)](https://img.qammunity.org/2022/formulas/mathematics/high-school/26u916qvy26mbuborwu2boorbd8xwdq0qr.png)
This gives:
![y = \{1,2,3,4,5,6\} - (\{1,2\} u \{3,4,5\})](https://img.qammunity.org/2022/formulas/mathematics/high-school/n179hmct59cn37ws1ld56kcmrmteyz7lws.png)
![y = \{1,2,3,4,5,6\} - \{1,2,3,4,5\}](https://img.qammunity.org/2022/formulas/mathematics/high-school/uyx5hbmp7xx89w46x8ueoh4txw2jk8h3u2.png)
Remove common elements
![y = \{6\}](https://img.qammunity.org/2022/formulas/mathematics/high-school/19obz09u61amm11x9cteucp3g70f1jua8n.png)
Hence, the set B is:
![B = \{\{x\},\{y\}\}](https://img.qammunity.org/2022/formulas/mathematics/high-school/3ejsi6vauroppc5b2nop5qkjyem3ql64n1.png)
![B = \{3,4,5,6\}](https://img.qammunity.org/2022/formulas/mathematics/high-school/lajo9jqr32hv9p549rq0p5gpplf7yyn24i.png)