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An athlete kicks a soccer ball that starts at rest so that it leaves their foot with a speed of 10m/s from the top o f a rectangular shaped canyon. If the athlete's foot is in contact with the ball for only 0.02 seconds, determine the accceleration of the ball during the kick.

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Answer:


a=500m/s^2

Step-by-step explanation:

We need only to apply the definition of acceleration, which is:


a=(v_f-v_i)/(t_f-t_i)

In our case the final velocity is
v_f=10m/s, the initial velocity is
v_i=0m/s since it departs from rest, the final time is
t_f=0.02s and the initial time we are considering is
t_i=0s

So for our values we have:


a=(10m/s-0m/s)/(0.02s-0s)=500m/s^2

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