Answer: 1953125
Explanation:
The given sequence = 1, 5, 25, 125, ….
We can rewrite the terms of the above sequence as (power of 5):
![5^0,\ 5^1,\ 5^2,\ 5^3\ ,....](https://img.qammunity.org/2020/formulas/mathematics/high-school/58zf0rd0kgrjgmcxeaksn9q7n4zhejkqv7.png)
Formula for each term :
![f(n)=5^(n-1)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ok2o2hnjdj46wvj9an3rnc95p0lwux1h0x.png)
To find the 10th term , we substitute n=10 , we get
![f(10)=5^(10-1)=5^9\\\\=5*5*5*5*5*5*5*5*5\\\\=1953125](https://img.qammunity.org/2020/formulas/mathematics/high-school/pounjwuuofia2zp0xqywoaywg7nrb97iel.png)
Hence, the 10th term of the sequence.= 1953125