Question

. A standard letter-sized piece of paper has a length and width of 8.5 inches by 11 inches.

d. What would the area be after 7 folds?

Answer 1

Area after 7 folds = 0.73 inch²

Explanation:

After 1 fold width or length reduces to half.

Area = Length x width

So after 1 fold area will reduce to half.

So we have

`\texttt{Area after n folds =}\frac{\texttt{Initial area}}{2^{\texttt{number of folds}}}`

Initial area = 8.5 x 11 = 93.5 inch²

Number of folds = 7

`\texttt{Area after 7 folds =}\frac{\texttt{Initial area}}{2^(7)}\\\\\texttt{Area after 7 folds =}(93.5)/(128)=0.73inch^2`

Area after 7 folds = 0.73 inch²