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A standard letter-sized piece of paper has a length and width of 8.5 inches by 11 inches.

b. If the paper were folded completely in half, what would be the area of the resulting rectangle?

1 Answer

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Answer:

Area of the resulting rectangle = 23.375 inch²

Explanation:

After 1 fold width or length reduces to half.

Area = Length x width

So after 1 fold area will reduce to half.

So we have


\texttt{Area after n folds =}\frac{\texttt{Initial area}}{2^{\texttt{number of folds}}}

Initial area = 8.5 x 11 = 93.5 inch²

Here the paper were folded completely in half, length is reduced to half and width reduced to half, that is

Number of folds = 2


\texttt{Area after 2 folds =}\frac{\texttt{Initial area}}{2^(2)}\\\\\texttt{Area after 2 folds =}(93.5)/(4)=23.375inch^2

Area after 2 folds = 23.375 inch²

Area of the resulting rectangle = 23.375 inch²

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