Answer:
a) P(x) = {0.1667 for x in (3,9) , 0 otherwise}
b) P(x≤6) = 0.5
c) P(4 < x ≤ 6) = 0.3333
d) P(X > 4 | X ≤ 6) = 0.3333 or 1 *see below*
Explanation:
a)
Since it is a uniform distribution you can imagine it as a rectangle which extends from a = 3 to b = 9 and whose total area is 1.
Therefore the height must be equal to the inverse of the side:
P(X) = 1/(b-a) = 1/(9-3)= 1/6 for every x in (3,9) and 0 otherwise
P(X) = 0.1667
b)
To find this probability we must find the area of the rectangle which extends from 3 to 6 and whose height is equal to P(x)
That is:
P(X ≤ 6) = (6-3)/(9-3) = 3/6 = 1/2 = 0.5
That make sense since 6 is half way between 3 and 9
c)
Similar to b) but now we consider tha base of the rectangle from 4 to 6:
P(4 < X ≤ 6) = (6-4)/(9-3) = 2/6 = 1/3 = 0.3333
d)
If '' | '' means " or ", the probability is one, since every number in the range (3,9) is either higher than 4 or less than 6.
If " | " means " and " the answer is the same as in c , that is because 4<x≤6 is the set of numbers which are higher than 4 and at most 6 which can be expressed as x>4 and x≤6