Answer:

Step-by-step explanation:
Kepler's 3rd Law tells us that:

where a is the semi-major axis, M the mass of the much more massive central object (in this case Jupiter, so
), T the orbital period and
the gravitational constant.
If we count the days between July 21, 2019 and September 12, 2019 we get 53 days , from there we can calculate the seconds easily by doing 53(24)(60)(60), obtaining 4579200 seconds. We put this then in our equation:
![a=\sqrt[3]{((GM)/(4\pi^2))T^2}=\sqrt[3]{(((6.67*10^(-11)Nm^2/Kg^2)(1.898*10^(27)Kg))/(4\pi^2))(4579200s)^2}=4066435070m=4066435km](https://img.qammunity.org/2020/formulas/physics/college/ytzo7o3v0sqf7e138to8ssilhsk4vjezrn.png)