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A 6 kg block is sliding down a horizontal frictionless surface with a constant speed of 5 m/s. It then slides down a frictionless ramp to another horizontal frictionless surface which is 2 m lower than the first horizontal surface. What is the constant speed with which the block is now sliding along this new horizontal surface?

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2 votes

Final answer:

To find the constant speed of the block sliding along the new horizontal surface, use the principle of conservation of mechanical energy.

Step-by-step explanation:

To find the constant speed of the block sliding along the new horizontal surface, we can use the principle of conservation of mechanical energy. Since the first horizontal surface is frictionless, the block's initial mechanical energy is equal to its final mechanical energy on the new horizontal surface.

On the first horizontal surface, the block only has kinetic energy, which is given by the formula K = 1/2mv^2.

On the new horizontal surface, the block still has kinetic energy, but it also has potential energy due to the change in height. The potential energy is given by the formula U = mgh, where m is the mass of the block, g is the acceleration due to gravity, and h is the change in height.

Setting the initial and final mechanical energies equal to each other, we can solve for the final speed of the block on the new horizontal surface.

User Hatik
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5 votes

Answer:

5in

Step-by-step explanation:

User Setop
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5.8k points