Question

A 500 kg roller coaster has a high hill of 9 meters and a small hill of 4 meters. The small hill comes immediately after the large hill. If the car just starts rolling at the top of the high hill, how fast will it be going at the top of the small hill?

Answer 1

Answer:
`v_2=9.89 m/s`

Step-by-step explanation:

Given

mass of roller coaster (m)=500 kg

Height of high hill=9 m

height of low hill=4 m

As total Energy is conserve therefore

Total Energy at high hill=Total Energy at low hill

Energy =Potential Energy + kinetic Energy

`mgh_1+(mv^2)/(2)=mgh_2+(mv_2^2)/(2)`

At top Kinetic energy is zero

`g* 9+0=g* 4+(v_2^2)/(2)`

`2* 5* g=v_2^2`

`v_2=√(2* 5* 9.8)`

`v_2=9.89 m/s`