Question

Let us assume Kleiber's law, that the metabolic rate of an organism is proportional to its mass to the 3/4's power, is applicable to all living creatures. If this is true, and if the metabolic rate of a 100 kg animal is 100 Watts (Joules per second), what would be the metabolic rate (in Watts) of a 29 kg creature? g

Answer 1

Metabolic rate is 39.52 W

Solution:

As per the question:

Metabolic Rate, MR' = 100 W

Mass of the animal, m = 100 kg

Mass of the creature, m' = 29 kg

Kleiber's law expresses that the metabolic pace of a creature scales to the 3/4 intensity of the mass.

Now, considering kleiber's law to be true:

Metabolic Rate,
`MR = MR'* ((m')/(m))^{(3)/(4)}`

`MR = 100* ((29)/(100))^{(3)/(4)} = 39.52 W`

Answer 2

0.22 W

Step-by-step explanation:

given:

MR1= 100 Watts (Joules per second)

M1=0.029 kg

M2=100 kg

Metabolic Rate =MR1*(M1/M2)^(3/4)

=100*(0.029/100)^(3/4)

=0.22 W