Question

A man with pattern baldness and a woman who has no baldness have a son who develops pattern baldness. Their son has a daughter who also develops pattern baldness. They determine that her expression of this trait is not a symptom of a medical condition. If her mother does not have pattern baldness, the daughter's genotype is ________ and her mother's genotype is ________.a. BB, bbb. BB, Bbc. bb, BBd. Bb, Bbe. bb, Bb

Answer 1

bb, Bb.

Step-by-step explanation:

Pattern baldness is the example of the sex influenced traits. The traits is more influenced in male than the female. If the male is heterozygous for the trait they will show the trait and the female will not show the trait.

A man with pattern baldness has son with the pattern baldness. The genotype of the sun can be Bb or bb. The daughter has pattern baldness. Her genotype is bb because female will only show the trait if they have homozygous recessive condition. The mother's genotype is Bb as she is a carrier and responsible to pass the characteristic trait gene to his daughter. Hence, the daughter's genotype is bb and mother's genotype is Bb.

Thus, the correct answer is option (e).