Question

A block of ice with mass 5.50 kg is initially at rest on a frictionless, horizontal surface. A worker then applies a horizontal force F⃗ to it. As a result, the block moves along the x-axis such that its position as a function of time is given by x(t)

Answer 1

x ( t ) = F / 5.5 t²

Step-by-step explanation:

acceleration dv / dt = F / 5.5

dv = F / 5.5 dt

integraring on both sides

v = F / 5.5 t + c

when t = 0 , v = 0

c = 0

v = F / 5.5 t

ds / dt = F / 5.5 t

integrating on both sides

s = F / 5.5 t² + c₁

when t = 0 , s = 0

c = 0

so

x ( t ) = F / 5.5 t²

This is the required relation.