109k views
2 votes
Judy is playing a card game. She needs to select two cards below that have a sum greater

than 5. Which two cards should she select? Prove it.

2 (2)/(5)


2 (2)/(7)


1 (7)/(8)


2 (1)/(10)


2 (5)/(8)
​​
(posted again to put this in the right subject)

1 Answer

7 votes

Answer:


2(2)/(5)  + 2(5)/(8) \simeq 5


2(2)/(7)  + 2(5)/(8)  \simeq 5

Explanation:

Mixed fraction
a(b)/(c) can be converted into like or unlike fractions.

Here,
a(b)/(c) =  (ac +b)/(b)

So, convert all the given fractions as follows:


2(2)/(5) =  (2(5) +2)/(5) = (12)/(5)  =2.4


2(2)/(7) =  (2(7) +2)/(7) = (16)/(7)  =2.4


1(7)/(8) =  (1(8) +7)/(8) = (15)/(8)  =1.8


2(1)/(10) =  (2(10) + 1)/(10) = (21)/(10)  =2.1


2(5)/(8) =  (2(8) +5)/(8) = (21)/(8)  =2.6

Here, No Two fractions on addition gives a sum greater than 5.

But an approximate sum of 5 is given by adding 2.4 + 2.6 = 5


2(2)/(5)  + 2(5)/(8) \simeq 5

or
2(2)/(7)  + 2(5)/(8)  \simeq 5

User Longfish
by
8.4k points