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You push downward on a box at an angle 25° below the horizontal with a force of 750 N. If the box is on a flat horizontal surface for which the coefficient of static friction with the box is 0.61, what is the mass of the heaviest box you will be able to move?

User Afo B
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1 Answer

7 votes

Answer:

The heaviest box that can be moved will have a mass of 81.36 kg

Solution:

As per the question:

Angle,
\theta = 25^(\circ)

Force, F = 750 N

Static Friction Coefficient,
\mu_(s) = 0.61

Now,

The acceleration of the box is zero.

The net force,
F_(net) that acts on the box is zero, thus:


Fcos25^(\circ) = \mu_(s)mg + \mu_(s)Fsin25^(\circ)


m = (Fcos25^(\circ) - \mu_(s)Fsin25^(\circ))/(\mu_(s)* g)


m = (750cos25^(\circ) - 750sin25^(\circ))/(0.61* 9.8) = 81.36\ kg

User Binar Web
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