Question

An old refrigerator consumes 247 W of power. Assuming that the refrigerator operates for 19 hours everyday, what is the annual operating cost of the refrigerator, if the cost of electricity is $0.06 per kWh? Group of answer choices 1712.94 $ 102776.7 $ 102.78 $ 0.28 $

Answer 1

102.78$

Step-by-step explanation:

First, you need to multiply the consumed potence by the hours of operation per day:

`247W*19(h)/(day) =4693(W*h)/(day)`

Now, a kilowatt is equivalent to 1,000 watts, so let's convert from watts to kilowatts:

`4693(W*h)/(day)*(1kW)/(1000W) =4.693(kWh)/(day)`

We have determined how many kWh the refrigerator consumes per day, now let's multiply the previous result by 365 in order to find how many kWh it consumes per year:

`4.693(kWh)/(day)*(365 days)/(1 year)=1712.945(kWh)/(year)`

Finally let's multiply the amount of kilowatts per year by the cost of electricity:

`1712.945(kWh)/(year)*(0.06\$)/(kWh) =102.7767(\$)/(year)\approx102.78(\$)/(year)`