Question

Write a program TwoSmallest.java that takes a set of double command-line arguments and prints the smallest and second-smallest number, in that order. It is possible for the smallest and second-smallest numbers to be the same (if the sequence contains duplicate numbers).

Answer 1

The following code is written in java programming language:

public class TwoSmallest { //define class

public static void main(String[] args) { // define main function

if (args.length < 2) { //set the if condition

System.out.println("Enter double values as command line arguments");

} else {

double minimum1 = Double.parseDouble(args[0]), minimum2 = Double.parseDouble(args[1]), n;

if (minimum1 > minimum2) { //set the if condition

double temp = minimum1;

minimum1 = minimum2;

minimum2 = temp;

}

for (int i = 2; i < args.length; i++) { //set the for loop

n = Double.parseDouble(args[i]);

if (n < minimum1) {

minimum2 = minimum1;

minimum1 = n;

} else if (n < minimum2) {

minimum2 = n;

}

}

System.out.println(minimum1);

System.out.println(minimum2);

}

}

}

Step-by-step explanation:

Here, we define a class "TwoSmallest" with public modifier.

Then, we define the main method.

Then, we set if condition and pass condition "args.length < 2".

Then we take three double type variable "minimum1", "minimum2" and "n".

Then, we set the if condition and pass condition if "minimum1 > minimum2", then set double type "temp" variable and swap between temp, minimum1 and minimum2.

Then, we set the for loop which is start from 2 and stops at "args.length"

Then, we set if condition and then we set its else part, after that we print the value of minimum1 and minimum2.