1 Answer

Jens H · Answer 1 · 2020-12-03T13:12:00+0000

For this case we have that the equation of a line of the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

$m = \frac {y2-y1} {x2-x1}$

We have the following points:

$(x1, y1): (7,2)\\(x2, y2): (2,12)$

Substituting:

$m = \frac {12-2} {2-7} = \frac {10} {- 5} = - 2$

Thus, the equation is of the form:

y = -2x + b

We substitute one of the points to find the cut point "b":

$2 = -2 (7) + b\\2 = -14 + b\\2 + 14 = b\\16 = b$

Thus, the equation is:

y = -2x + 16

Answer:

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