Question

Reduce the following fraction: -32abc/64a^2bc^2

a. - 1/2ac^2
b.- 16ac/^2
c.1ac^2/2
d. - 32/6ac^2

Answer 1

-1/(2ac)

Explanation:

-32/64=-1/2

the b's cancel each other out,

leaving you with ac on the denominator.

Answer 2

`-(1)/(2ac)`

Explanation:

Given:

`(-32abc)/(64a^2bc^2)`

Reduce this fraction.

Work with numbers and different letters separately:

1. Numbers:

`(-32)/(64)=-(32)/(32\cdot 2)=-(1)/(2)`

2. Letter a:

`(a)/(a^2)=(a)/(a\cdot a)=(1)/(a)`

3. Letter b:

`\frac{b}b}=1`

4. Letter c:

`(c)/(c^2)=(c)/(c\cdot c)=(1)/(c)`

Hence,

`(-32abc)/(64a^2bc^2)=-(1)/(2)\cdot (1)/(a)\cdot (1)/(c)=-(1)/(2ac)`