Question

A rectangle has a perimeter of 56 in. The length is four more than the width. What are the length and width of the rectangle

Answer 1

Width = 12 in

Length = 16 in

Explanation:

Let, the Width of the rectangle = w in

Now, the length of the rectangle = (w + 4) in

Now, Perimeter = 56 in

Also, we know that

Perimeter of the Rectangle = 2 (Length +Width)

or, 2 (Length +Width) = 56

⇒ 2(w + 4 +w) = 56

or, 4w =56 -8

width = 12 in

So, Length = w + 4 = 12 + 4 = 16 in