Question

A projectile is launched on Earth and flies without air resistance. Another projectile is launched with the same initial velocity on the moon, where the acceleration due to gravity is one sixth as large. How does the range of the projectile on the Moon compare with the range of the projectile on Earth? Assume it is launched over level ground in both cases.

Answer 1

Answer:6 times the range of Earth

Step-by-step explanation:

Given

first projectile is launched and second Projectile is launched on moon surface from same height

acceleration due to gravity on moon is
`(g)/(6)`

Range of Projectile
`=(u^2\sin 2\theta )/(g)`

Where u=initial velocity

`\theta`=launch angle

`R_1=Range\ on\ earth\=(u^2\sin 2\theta )/(g)`

`R_2=Range\ on\ moon\ =(u^2\sin 2\theta )/((g)/(6))`

`R_2=(6u^2\sin 2\theta )/(g)`

`R_2=6R_1`

so range on moon is six times as compare to range on earth