Answer:
AJ picks 252 pounds
Explanation:
Lets define the following letters for each name:
A is AJ
B is Blaze
L is Laurence
J is Jack
Now we will analyze the phrases one by one:
Blaze picks three times as many as Laurence means:
![B = 3 * L](https://img.qammunity.org/2020/formulas/mathematics/college/iwcmdvdvpffrd8zwpiaugrdjjasiryyf3h.png)
Jack picks twice as many as Blaze.
, ans using the previous one lets substitute B with 3 * L
![J = 2 * B = 2 * (3 * L)](https://img.qammunity.org/2020/formulas/mathematics/college/b6foohh1w79jkjy901s6kznoo7aneh5uz1.png)
![J = 6 * L](https://img.qammunity.org/2020/formulas/mathematics/college/lbdsslnjpph54kexuzp7estms0roocmokz.png)
Aj picks three times as many as Laurence.
![A = 3 * L](https://img.qammunity.org/2020/formulas/mathematics/college/4g4x558ee6dqqja4weu8bd5jnpkubr2wno.png)
The total weight of the oranges is 1092 pounds.
![A + B + J + L = 1092](https://img.qammunity.org/2020/formulas/mathematics/college/2akvaih3s79xpu60tb6odca6sodg27tx5q.png)
We replace A, B & J in the last equation, with the previous results:
![A + B + J + L = 1092](https://img.qammunity.org/2020/formulas/mathematics/college/2akvaih3s79xpu60tb6odca6sodg27tx5q.png)
, grouping using L as common factor:
![(3+3+6+1) * L = 1092](https://img.qammunity.org/2020/formulas/mathematics/college/nssb824uv87nwgdeznz7i3mnf9ynlxoa7c.png)
, then isolating L:
![L = 1092 / 13](https://img.qammunity.org/2020/formulas/mathematics/college/l2b9bldxlxky6ztweqbjd2ar2ct1mcvei0.png)
pounds (for Laurence)
Finally replacing L in the previous equations:
pounds (for Aj)
pounds (for Blaze)
pounds (for Jack)