Question

Smedly has just drawn two rectangles. The length of the first rectangle is 4 cm more than the length of the second. The width of the first is 9 cml the width of the second is 6 cm. If the area of the first rectangle is 96cm

Answer 1

The area of the second rectangle is
`A=42cm^(2)`

Explanation:

Please see the picture below.

Let´s name the length of the second rectangle as x, so the length of the first rectangle will be 4+x.

The formula of the area of the rectangle is given by

`A=length*width`

Replacing values:

`96cm^(2)=(4cm+x)*9cm`

`96cm^(2)=36cm+9cm*x`

Solving for x:

`96cm^(2)-36cm=9cm*x`

`60cm=9cm*x`

`x=(60cm)/(9cm)`

`x=7cm`

Find the area of the second rectangle:

`A=length*width`

`A=x*6cm`

`A=7cm*6cm`

`A=42cm^(2)`