Question

A projectile is thrown with a wind. The wind produces a constant acceleration of 2 m/s/s in the same direction as the projectile’s horizontal direction. The projectile is launched with a velocity of 20 m/s at an angle of 30°. The projectile lands at the same height as it was launched. a. How far from the launch point does the projectile land? Do this problem again with no numbers.

Answer 1

Step-by-step explanation:

It is given that,

Initial speed of the projectile, u = 20 m/s

It is launched at an angle of 30 degrees . Let the projectile will land at a distance R from the launch point. It is called the range of the projectile. Mathematically, it is given by :

`R=(u^2\ sin2\theta)/(g)`

`R=((20)^2\ sin2(30))/(9.8)`

R = 35.34 meters

So, it will land at a distance of 35.34 meters from the launch point.

Let u is the speed with which the projectile is launched. The angle formed by the projectile is θ. The distance covered by the projectile form its launch point to the other point is called the range of the projectile. it is given by :

`R=(u^2\ sin2\theta)/(g)`

Hence, this is the required solution.