Question

How many moles of dinitrogen tetroxide (N2O4) are in 6.49 x 109 particles?

1.08 x 10–14 mol N2O4

3.091 x 1033 mol N2O4

6.02 x 1023 mol N2O4

1.08 x 10–23 mol N2O4

Answer 1

1.08 × 10⁻¹⁴ moles of N2O4

Step-by-step explanation:

Given data:

Moles of dinitrogen tetroxide = ?

Number of particles = 6.49×10⁹

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions , particles and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.

1 mole contain 6.022 × 10²³ particles.

6.49×10⁹ particles × 1 mole / 6.022 × 10²³ particles

1.08 × 10⁻¹⁴ mol

Answer 2

Answer: There are
`1.08 * 10^(-14)` moles
`N_(2)O_(4)` present in
`6.49 * 10^9` particles.

Step-by-step explanation:

According to the mole concept, 1 mole of a substance contains
`6.022 * 10^(23)` particles.

Hence, number of moles present in
`6.49 * 10^9` particles are calculated as follows.

No. of moles =
`(6.49 * 10^9)/(6.022 * 10^(23))` mol

=
`1.08 * 10^(-14)` mol

Thus, there are
`1.08 * 10^(-14)` moles
`N_(2)O_(4)` present in
`6.49 * 10^9` particles.