Question

Find the equation of a line that passes through the point (-5,4) and is perpendicular to 6x-36y

Answer 1

`y = - 6x - 2`

Step-by-step explanation

The given line is

`6x - 36y = k`

where k is the missing constant from the given equation( this has no effect on the solution in anyway)

We solve for y to get;

`y = (1)/(6)x - (k)/(36)`

The slope of this line after comparing to

y=mx+c is

`m = (1)/(6)`

The negative reciprocal is m=-6

The equation of the required line that passes through (-5,4) is given by

`y - 4 = - 6(x - - 5)`

We multiply through by 6 to get:

`y - 4 = - 6x - 30`

We expand to get;

`y = - 6x - 26`