Question

Examine the chemical reaction and lab scenario.

2Fe2S3+9O2→2Fe2O3+6SO2

3.17 g of iron(III) sulfide (Fe2S3) reacts with an excess amount of oxygen at standard temperature and pressure. The theoretical yield of sulfur dioxide (SO2) is 3.81 g. However, during a lab, only 3.37 g are produced.

What is the percent yield of sulfur dioxide?

94.41% SO2

81.36% SO2

44.00% SO2

88.45% SO2

Answer 1

Step-by-step explanation:

Percentage Yield

= (3.37g/3.81g) * 100% = 88.45%.

Therefore 88.45% SO2 is the percentage yield.