Question

MATH three consecutive integers with sum of -99​

Answer 1

Step-by-step explanation:Since their sum is

99

, we have:

x+x+1+x+2=99

3x+3=99

3x= 96

X=32

Thus, the three numbers are: 32, 33, 34

Answer 2

Let x = 1st integer
X + 1 = 2nd integer
X + 2 = 3rd integer

X + x + 1 + x + 2 = -99
3x + 3 = -99
3x = -102
X = -34
X + 1 = -33
X + 2 = -32