Step-by-step explanation:
It is given that, there are two points situated above a current-carrying wire. Point B is located at a distance R from the wire, which is twice as far from the wire as point A such that,
![r_B=R](https://img.qammunity.org/2020/formulas/physics/high-school/nv946u4c4xiqq1vrwyruby2xfp8qwfcc2j.png)
And
![r_A=R/2](https://img.qammunity.org/2020/formulas/physics/high-school/o4fckkycux4zs40mp8rk8d515078b8sxk9.png)
We know that the magnetic field at a distance R is inversely proportional to the distance from wire as :
![B=(\mu_o)/(2\pi)(I)/(r)](https://img.qammunity.org/2020/formulas/physics/high-school/hxyextj2q0lvvenad1ityj14yeaiw3eirh.png)
![B_A\propto(1)/((R/2))](https://img.qammunity.org/2020/formulas/physics/high-school/w30b3ymvlw2lpdnsw39bh44fnef4auepaf.png)
![B_B\propto(1)/((R))](https://img.qammunity.org/2020/formulas/physics/high-school/nfn355v61nalw8ilmz2pt1j8h8k7c312fd.png)
![(B_A)/(B_B)=(1/(R/2))/(1/R)](https://img.qammunity.org/2020/formulas/physics/high-school/j9qp3s73069imjgr3nj9ng4o4c0y58autq.png)
![(B_A)/(B_B)=(2)/(1)](https://img.qammunity.org/2020/formulas/physics/high-school/akh9tdw3enltheu0zhdwex28mhvwk6fav3.png)
![B_A=2B_B](https://img.qammunity.org/2020/formulas/physics/high-school/24catg2iz11aj95iqiibyinpmt3905use6.png)
So, the magnetic field at point A larger than the magnetic field at point B by a factor of 2. Hence, this is the required solution.