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Two points, point A and point B, are situated above a current-carrying wire. Point B is located at a distance R from the wire, which is twice as far from the wire as point A. By what factor is the magnetic field at point A larger or smaller than the magnetic field at point B?

1 Answer

4 votes

Step-by-step explanation:

It is given that, there are two points situated above a current-carrying wire. Point B is located at a distance R from the wire, which is twice as far from the wire as point A such that,


r_B=R

And
r_A=R/2

We know that the magnetic field at a distance R is inversely proportional to the distance from wire as :


B=(\mu_o)/(2\pi)(I)/(r)


B_A\propto(1)/((R/2))


B_B\propto(1)/((R))


(B_A)/(B_B)=(1/(R/2))/(1/R)


(B_A)/(B_B)=(2)/(1)


B_A=2B_B

So, the magnetic field at point A larger than the magnetic field at point B by a factor of 2. Hence, this is the required solution.

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