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The coordinates of the vertices of quadrilateral ABCD are A(-5, 1), B(-2,5), C(5, 3),

and D(2, -1)

Drag and drop the choices into each box to correctly complete the sentences.

The slope of AB is

the slope of BC is

the slope of CD is:

and the

slope of AD is

1. Quadrilateral ABCD is

because

User Samori
by
8.2k points

2 Answers

2 votes

Explanation:

To calculate a slope, we need to apply:
m=(y_(2)-y_(1)  )/(x_(2)-x_(1)  )

Applying formula to each slope:


m_(AB)=(5-1)/(-2-(-5)) = (4)/(3)  \\m_(BC)=(3-5)/(5-(-2)) =(-2)/(7)\\m_(CD)=(-1-3)/(2-5)=(-4)/(-3) =(4)/(3)

So, as you can see, there are equal pair of slopes, meaning that they are parallels, which demonstrate that it's actually a quadrilateral figure.

User Mirkancal
by
8.2k points
3 votes

Answer: slope (AB)= 4/3 slope(BC)=-2/7 slope(CD) =4/3 slope(AD) = -2/7

Explanation:

To find the slope, lets take a pair ones after the other

A(-5, 1) B(-2,5)

Given; x₁ =-5 y₁ = 1 x₂=-2 y₂=5

slope(AB) = y₂ - y₁ / x₂ - x₁

=5 - 1 / -2--5

=4/3

slope BC

B(-2, 5) c(5,3)

Given;

x₁=-2 y₁=5 x₂=5 y₂=3

slope(BC) = y₂ - y₁ / x₂ - x₁

= 3-5 / 5--2

=-2/7

slope CD

C(5, 3) D(2, -1)

Given;

x₁ = 5 y₁ = 3 x₂ = 2 y₂= -1

slope(CD)= y₂ - y₁ / x₂ - x₁

= -1-3 / 2-5

= -4/-3

= 4/3

slope AD

A(-5, 1) D(2, -1)

Given;

x₁ = -5 y₁ =1 x₂ =2 y₂ =-1

slope(AD) = y₂ - y₁ / x₂ - x₁

= -1-1 / 2--5

= -2/7

User Jumand
by
8.7k points

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