Question

In a Brinell hardness test, a 1500-kg load is pressed into a specimen using a 10-mm-diameter hardened steel ball. The resulting indentation has a diameter = 3.2 mm. (a) Determine the Brinell hardness number for the metal. (b) If the specimen is steel, estimate the tensile strength of the steel.

Answer 1

a) BHN = 181.606

b) UTS = 635.621 MPa

Step-by-step explanation:

given,

Load = 1500 kg

steel ball of diameter (D) = 10 mm

resulting indentation diameter (d)= 3.2 mm

brinell hardness number

`BHN = (2P)/((\pi D)(D - √(D^2-d^2)))`

`BHN = (2* 1500)/((\pi * 10)(10 - √(10^2-3.2^2)))`

`BHN = (3000)/(16.519)`

BHN = 181.606

b) The tensile strength of the steel

UTS = 3.5 (BHN)

UTS = 3.5 x (181.606)

UTS = 635.621 MPa