Question

9. Suppose that 25.0 mL of a gas at 725 mm Hg and 20°C is converted to standard

pressure and temperature. What would be the new volume?

Answer 1

V₂ = 22.23 mL

Step-by-step explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 25 mL

Initial pressure = 725 mmHg (725/760 =0.954 atm)

Initial temperature = 20 °C (20 +273 = 293 K)

Final pressure = standard = 1 atm

Final temperature = standard = 273.15 K

Final volume = ?

Solution:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 0.954 atm × 25 mL × 273.15 K / 293 K × 1 atm

V₂ = 6514.63 mL . atm . K / 293 K . atm

V₂ = 22.23 mL