Question

Which of the following set of quantum numbers correctly describes an electron in a 5d orbital? A) n = 5, l = 3, ml = +3, ms = +1/2 B) n = 5, l = 2, ml = 0, ms = +1/2 C) n = 5, l = 2, ml = +3, ms = +1/2 D) n = 5, l = 3, ml = +2, ms = +1 E) n = 5, l = 2, ml = +2, ms = +1

Answer 1

B.
`n=5, l=2,m_l=0,m_s=+(1)/(2)`

Explanation:

We are given that an electron in a 5d orbital

We have to find the set of quantum numbers correctly describes an electron in a 5d orbital.

We know that

n=Principle quantum number

Therefore, n=5

Angular momentum quantum number =l=0,1,2,3,..(n-1)

l=0 =s-orbital

l=1=p- orbital

l=2=d=orbital

l=3=f orbital

Therefore, l=2

Magnetic quantum number=
`m_l=-l,..,0,..l`

`m_l=-2,-1,0,1,2`

5d orbital have only one electron Magnetic quantum number have no fixed values

Therefore,we can take
`m_l=0`

Spin quantum number
`m_s=\pm(1)/(2)`

5d orbital have only one electron .Then, it has spin-up

Therefore,
`m_s=+(1)/(2)`

Answer:B.
`n=5, l=2,m_l=0,m_s=+(1)/(2)`