Answer:
S(-3,-1)
Explanation:
If the points P(5, 7) and Q(-1, 1) lie on the graph of y = x + 2 then they satisfy the its equation i.e y=x+2
If R(1, - 1) is collinear with P and Q, then it must also satisfy y=x+2
We substitute x=1 and y=-1 to get:
![- 1 = 1 + 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ytdvarkbpf806og28c59jl9g7kmojksuja.png)
This gives
![- 1 = 3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w7v5ri602dx7djjv5kxk3dsamtvcg5g1t4.png)
Buy this is not true. Hence R(1,-1) is not collinear with P and Q.
Similarly, we the coordinates of S(-3,-1) to get:
![- 1 = - 3 + 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sz3xhn2z6ghqa5civw5bt3whxdktnoquo3.png)
This gives us
![- 1 = - 1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/g6dq7rhvxcp2zj22nkw2nbagc151pnuy1k.png)
This statement is true.
Hence S(-3,-1) is collinear with P and Q