Question

Factor completely. 6x3+39x2+63x6x3+39x2+63x

x(3x + 9)(2x + 7)

(6x + 21)(x + 3)

x(x + 3)(6x + 21)

6x3+39x2+63x6x3+39x2+63x

3x(2x + 7)(x + 3)

(3x + 9)(2x + 7)

Answer 1

`3x(2x+3)(x+7)`

Explanation:

The given polynomial expression is
`6x^3+39x^2+63x`

We factor the factor the greatest common factor of 3x to get;

`3x(2x^2+13x+21)`

We now factor the quadratic trinomial by splitting the middle term

`3x(2x^2+7x+6x+21)`

`3x(2x(x+7)+3(2x+7))`

`3x(2x+3)(x+7)`

The completely factored form is
`3x(2x+3)(x+7)`