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Find a quadratic polynomial the sum and product of whose zeroes are -3 and 2 respectively​

User Sadiel
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1 Answer

11 votes

Answer:


P(x)=x^2+x-6

Explanation:

Quadratic Polynomial

Assume we have a polynomial factored as:

P(x)=a(x-m)(x-n)

Where m and n are the zeros of P(x).

Operating:


P(x)=a(x^2-(m+n)x+mn)

Note the coefficient of x is the negative sum of the zeros and the independent term is the product of the zeros.

If we are given the zeros m=-3 and n=2, then:


P(x)=a(x^2-(-3+2)x+(-3)(2))


P(x)=a(x^2+x-6)

We can choose any value for a, for example, a=2:


P(x)=2x^2+2x-12

For a=1:


P(x)=x^2+x-6

User Ollo
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