Answer:
The length of the rectangle is 51 meters and the width is 70 meters.
Explanation:
Let us assume that the length of the rectangle is L and the width of the same rectangle is W.
it is given in the problem that, the width of the rectangle is 19 meters more than the length.
Hence, L+19 =W ......(1)
Again, the perimeter of the rectangle is given by 2(L+W), which is given to be 242 meters.
So, 2(L+W) =242, ⇒L+W =121 ..... (2)
Now, solving equations (1) and (2) by substitution method, we get,
L+(L+19) =121, ⇒2L =102, ⇒ L =51 meters.
Now, from equation (1), W=L+19 =70 meters.
Therefore, the length of the rectangle is 51 meters and the width is 70 meters. (Answer)