Question

What are the zeros of the quadratic function f(x) = 2x2 + 8x – 3?

Answer 1

ANSWER IS A!!!!!!!!!!!!

Explanation:

Answer 2

`\large\boxed{x=-2-\sqrt{(11)/(2)}\ \text{and}\ x=-2+\sqrt{(11)/(2)}}`

Explanation:

`f(x)=2x^2+8x-3\\\\\text{You can use the quadratic formula:}\\\\ax^2+bx+c=0\\\\x=(-b\pm√(b^2-4ac))/(2a)\\\\\text{We have}\ a=2,\ b=8,\ c=-3\\\\\text{Substitute:}\\\\b^2-4ac=8^2-4(2)(-3)=64+24=88\\\\√(b^2-4ac)=√(88)=√(4\cdot22)=\sqrt4\cdot√(22)=2√(22)\\\\x=(-8\pm2√(22))/(2(2))=(-8)/(4)\pm(2√(22))/(4)=-2\pm(√(22))/(2)=-2\pm(√(22))/(\sqrt4)\\\\x=-2\pm\sqrt{(22)/(4)}=-2\pm\sqrt{(11)/(2)}`